Nuprl Lemma : subtype-fpf2 11,40

A:Type, B1,B2:(AType).
(a:A. subtype_rel(B1(a); B2(a)))  subtype_rel(fpf(Aa.B1(a)); fpf(Aa.B2(a))) 
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Definitionsx:AB(x), P  Q, x(s), fpf(Aa.B(a)), t  T, subtype(ST), suptype(ST), xt(x), prop{i:l}
Lemmasl member wf, fpf wf

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